Question

Два велосипеда отправились одновременно навстречу друг другу s=60 встретились через 2 часа, определить скорость каждого если у одного на 2км/ч скорость больше

Answer 1

2x+2(x+2)=60      2x+2x+4=60     4x=56      x=14     скорость первого 14, скорость второго 14+2=16

Answer 2

(x*2)+((x+2)*2)=60 составила уравнение и просто решать 

Answer 3

Problem Analysis

We have two bicycles that start simultaneously and travel towards each other. They meet after 2 hours, and the total distance between them is 60 km. We need to determine the speed of each bicycle, given that one bicycle is traveling 2 km/h faster than the other.

Solution

Let's assume the speed of the slower bicycle is x km/h. Therefore, the speed of the faster bicycle will be (x + 2) km/h.

We know that the distance traveled by each bicycle is equal to the product of its speed and time. Since they meet after 2 hours, the distance traveled by the slower bicycle is 2x km, and the distance traveled by the faster bicycle is 2(x + 2) km.

According to the problem, the sum of the distances traveled by both bicycles is equal to 60 km. Therefore, we can write the following equation:

2x + 2(x + 2) = 60

Simplifying the equation:

2x + 2x + 4 = 60

4x + 4 = 60

4x = 60 - 4

4x = 56

x = 56 / 4

x = 14

So, the speed of the slower bicycle is 14 km/h, and the speed of the faster bicycle is (14 + 2) = 16 km/h.

Therefore, the speed of each bicycle is 14 km/h and 16 km/h, respectively.

Answer

The speed of the slower bicycle is 14 km/h, and the speed of the faster bicycle is 16 km/h.