Question

Боковая сторона равнобедренного треугольника на 5 см больше основания найдите стороны этого треугольника если его периметр равен 40 см ))))))))))))))))))))000

Answer 1

Пусть х основание треугольника. Тогда х+5 боковая сторона
х+(х+5)+(х+5)=40
3х=30
х=10 см основание треугольника
10+5=15 см боковая сторона

Answer 2

I can answer your question in detail. The side of an isosceles triangle is 5 cm longer than the base. Find the sides of this triangle if its perimeter is 40 cm.

Let x be the length of the base and y be the length of the side. Then we have:

- x + 2y = 40 (the sum of the sides is equal to the perimeter) - y = x + 5 (the side is 5 cm longer than the base)

Substituting the second equation into the first, we get:

- x + 2(x + 5) = 40 - x + 2x + 10 = 40 - 3x = 30 - x = 10

Therefore, the base is 10 cm and the side is 15 cm.

You can also find more information about isosceles triangles on the web .