Question

(х-2)квадрат=(х+3)квадрат

Answer 1

$(x-2)^{2}=(x+3)^{2}$
$x^{2}-4x+4=x^{2}+6x+9$
$x^{2}-4x-x^{2}-6x=9-4$
$-10x=5$
$x= \frac{5}{-10}$
$x=-0,5$

Answer 2

I can help you with math problems and other topics. You asked me to solve the equation $(x-2)^2=(x+3)^2$ in detail. Here are the steps:

1. Expand the squares on both sides: $x^2-4x+4=x^2+6x+9$. 2. Subtract $x^2$ from both sides: $-4x+4=6x+9$. 3. Subtract $6x$ from both sides: $-10x+4=9$. 4. Subtract $4$ from both sides: $-10x=5$. 5. Divide both sides by $-10$: $x=-\frac{1}{2}$.

Therefore, the solution is $x=-\frac{1}{2}$. You can check this by plugging it into the original equation and verifying that both sides are equal.

If you need more help with quadratic equations, you can use some online calculators and resources that I found for you. I hope this was helpful. Have a nice day!