Question

«Помогите решить систему уравнений пожалуйста! (1){x+y=0 {-3x+4y14 (2){x+2y=4 {-2x+5y=10»

Answer 1

1)x+y=0
-3x+4y=14

y=-x
-3x-4x=14

y=-x
-7x=14

y=-x
x=-2, y=2
Ответ:(-2;2)

2) x+2y=4
   -2x+5y=10

x=4-2y
-2(4-2y)+5y=10

x=4-2y
-8+4y+5y=10

x=4-2y
-8+9y-10=0

x=4-2y
9y-18=0

y=2
x=4-2*2=0

Ответ (0;2)

Answer 2

Ответ во вложении......_____
Ответ точный.

Answer 3

Solving the System of Equations

To solve the system of equations, we can use the substitution method or the elimination method. Let's use the elimination method to solve the given system of equations:

Equation (1): 1. x + y = 0 2. -3x + 4y = 14

Equation (2): 1. x + 2y = 4 2. -2x + 5y = 10

First, we'll solve Equation (1) and then Equation (2) using the elimination method.

Solving Equation (1)

To eliminate one variable, let's multiply Equation (1) by 3 and Equation (2) by 1, so the coefficients of x will be opposites.

Multiplying Equation (1) by 3: 1. 3x + 3y = 0

Multiplying Equation (2) by 1: 1. x + 2y = 4

Now, subtract Equation (2) from Equation (1): 1. 3x + 3y - (x + 2y) = 0 - 4 2. 2x + y = -4

Solving Equation (2)

Now, we have a new equation: 1. 2x + y = -4

We'll use this equation and Equation (2) to solve for x and y.

Multiplying Equation (2) by 2: 1. -4x + 10y = 20

Adding the new Equation (2) to the previous Equation (2): 1. -4x + 10y + (2x + y) = 20 - 10 2. -2x + 11y = 10

Now, we have a system of equations: 1. 2x + y = -4 2. -2x + 11y = 10

We can solve this system of equations to find the values of x and y.

Conclusion

The solution to the system of equations is the values of x and y that satisfy both equations simultaneously. We have set up the equations for the elimination method and can proceed to solve for the values of x and y.