Question

(3-2х)^2=0,04 решите там должно быть 2 ответа

Answer 1

(3-2х)^2=0,04
3-2х=0,2 и 3-2х=-0,2
-2х=-3+0,2 и -2х=-3-0,2
-2х=-2,8 и -2х=-3,2
х=1,4 и х=1,6

Answer 2

I can help you with math problems. To solve this equation, you need to expand the square, move all the terms to one side, and then use the quadratic formula to find the values of x. Here are the steps:

- $(3-2x)^2=0.04$ - $9-12x+4x^2=0.04$ - $4x^2-12x+8.96=0$ - $x=\frac{12\pm\sqrt{144-4\times4\times8.96}}{8}$ - $x=\frac{12\pm\sqrt{-102.24}}{8}$ - $x=\frac{12\pm i\sqrt{102.24}}{8}$

The equation has two complex solutions: $x=\frac{12+i\sqrt{102.24}}{8}$ and $x=\frac{12-i\sqrt{102.24}}{8}$. You can use a calculator to approximate the decimal values of these solutions. For more help with solving equations, you can check out these websites: [Mathway](https://www.mathway.com/ru/Algebra) or [Symbolab](https://ru.symbolab.com/solver/equation-calculator).