Question

3x + 3 y = 1 2x - 6y = - 10 решите систему уравнений методом алгебраического сложения

Answer 1

Смотри ответ на фотографии:

Answer 2

3x+3y=1
2x-6y=-10

3x+3y=1
x-3y=-5

3x+3y=1
4x=-4

-3+3y=1
x=-1

3y=4
x=-1

y=4/3
x=-1

Answer 3

Solving the System of Equations by the Method of Algebraic Addition

To solve the system of equations 3x + 3y = 1 and 2x - 6y = -10 using the method of algebraic addition, we can manipulate the equations to eliminate one of the variables.

First, let's manipulate the equations to make the coefficients of one of the variables equal and opposite. We can achieve this by multiplying one or both of the equations by a suitable constant.

Multiplying the first equation by 2 and the second equation by 3, we get:

6x + 6y = 2 (Equation 1) 6x - 18y = -30 (Equation 2)

Now, we can subtract Equation 2 from Equation 1 to eliminate the variable x:

24y = 32

Finally, we can solve for y:

y = 32 / 24 = 4 / 3

Next, we can substitute the value of y back into one of the original equations to solve for x. Let's use the first equation:

3x + 3 * (4 / 3) = 1 3x + 4 = 1 3x = 1 - 4 3x = -3 x = -1

So, the solution to the system of equations 3x + 3y = 1 and 2x - 6y = -10 is x = -1 and y = 4/3.