Question

Поезд, отходя от станции, равномерно увеличивает скорость движения и за 25 мин достигает скорости 60 км/ч. Найти ускорение поезда.

Answer 1

Так как начальная скорость равна 0 км/ч, найдем среднюю скорость движения: (0+30) / 2 = 15 км/ч.

10 мин. = 1/6 часа, =>

S= 1/6 * 15 = 2,5 км.

Answer 2

Calculation of Acceleration

To find the acceleration of the train, we can use the formula:

Acceleration (a) = Change in velocity (Δv) / Time taken (Δt)

Given that the train starts from rest and reaches a speed of 60 km/h (or 16.67 m/s) in 25 minutes (or 1500 seconds), we can calculate the acceleration.

Change in velocity (Δv) = Final velocity (v) - Initial velocity (u)

The initial velocity (u) is 0 m/s since the train starts from rest.

Change in velocity (Δv) = 16.67 m/s - 0 m/s = 16.67 m/s

Time taken (Δt) = 25 minutes = 1500 seconds

Now, we can substitute these values into the formula to calculate the acceleration:

Acceleration (a) = 16.67 m/s / 1500 s = 0.0111 m/s²

Therefore, the acceleration of the train is 0.0111 m/s².