Question

Братику задали задачу, вся семья не понимает. ОДНО ИЗ ЧИСЕЛ НА 5 БОЛЬШЕ ДРУГОГО. ПОСЛЕ ТОГО КАК МЕНЬШЕЕ ЧИСЛО УМЕНЬШИЛИ НА 20%, ИХ СУММА СТАЛА 59. НАЙДИ ЭТИ ЧИСЛА.

Answer 1

Пусть меньшее число х, тогда большее (х+5). Меньшее число уменьшили на 20%, значит оно стало составлять 100%-20%=80% от первоначального или 80/100*х=0,8х.
Составим и решим уравнение.
0,8х+(х+5)=59
0,8х+х+5=59
1,8х=59-5
1,8х=54
х=54:1,8
х=30 меньшее число
30+5=35 большее число

Ответ 30 и 35.

Answer 2

Problem Analysis

The problem states that one number is 5 more than the other. After the smaller number is reduced by 20%, their sum becomes 59. We need to find these two numbers.

Let's assume the smaller number is x. According to the problem, the larger number is 5 more than x, so it can be represented as (x + 5).

After the smaller number is reduced by 20%, it becomes 0.8x. The sum of the two numbers is 59, so we can write the equation:

x + (x + 5) = 59

Now we can solve this equation to find the values of x and (x + 5).

Solving the Equation

Let's solve the equation x + (x + 5) = 59 to find the values of x and (x + 5).

x + (x + 5) = 59 2x + 5 = 59 2x = 59 - 5 2x = 54 x = 54 / 2 x = 27

So the smaller number is 27. The larger number is 27 + 5 = 32.

Therefore, the two numbers are 27 and 32.

Answer

The two numbers are 27 and 32.