Question

Задайте формулой линейную функцию, график которой проходит через начало координат и параллелен прямой y=9x-3

Answer 1

Y=9x нарисуй и проверь;)

Answer 2

Linear Function Parallel to y=9x-3 and Passing Through the Origin

To find a linear function parallel to the line \(y=9x-3\) and passing through the origin, we can use the general form of a linear function, \(y=kx+b\), where \(k\) is the slope and \(b\) is the y-intercept.

Given that the line is parallel to \(y=9x-3\), the slope of the new line will be the same as the slope of \(y=9x-3\), which is 9. Since the line passes through the origin, the y-intercept, \(b\), is 0.

Therefore, the linear function that is parallel to \(y=9x-3\) and passes through the origin can be expressed as:

\(y=9x\)

This linear function has a slope of 9 and passes through the origin, as required.

Verification of the Claim

The linear function \(y=9x\) is parallel to the line \(y=9x-3\,\) and passes through the origin, as confirmed by the general form of a linear function \(y=kx+b\,\).

Therefore, the claim is verified based on the provided search results.