Question

Решите уравнения 3x2-7x=0 x2=4x

Answer 1

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Answer 2

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To solve the equations 3x^2-7x=0 and x^2=4x, we need to find the values of x that make them true.

For the first equation, we can factor out x from both terms and get x(3x-7)=0. Then, we can use the zero product property and set each factor equal to zero. This gives us x=0 or 3x-7=0. Solving for x, we get x=0 or x=\frac{7}{3}.

For the second equation, we can subtract 4x from both sides and get x^2-4x=0. Then, we can factor out x from both terms and get x(x-4)=0. Again, we can use the zero product property and set each factor equal to zero. This gives us x=0 or x-4=0. Solving for x, we get x=0 or x=4.

Therefore, the solutions are x=0, x=\frac{7}{3}, and x=4. You can check them by plugging them back into the original equations.

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