Question

1)3х⁷÷х-2х²·х⁴=? 2)ab·(-2)·(4a)³=? решите пожалуйста))

Answer 1

1) $3 x^{7-1}-2 x^{2+4}= 3 x^{6} -2 x^{6}= x^{6}$
2) $-128 a^{1+3}b= -128 a^{4}b$

Answer 2

1) To simplify the expression 3x^7/x - 2x^2 * x^4, we can apply the rules of exponents and perform the necessary calculations step by step.

First, let's simplify the division 3x^7/x. When dividing two terms with the same base, we subtract their exponents. In this case, the x terms cancel out, and we are left with 3x^(7-1) = 3x^6.

Next, let's simplify the multiplication 2x^2 * x^4. When multiplying two terms with the same base, we add their exponents. In this case, we have 2x^(2+4) = 2x^6.

Now, we can substitute the simplified expressions back into the original expression: 3x^6 - 2x^6.

Finally, we can combine like terms by subtracting the coefficients of the x^6 terms: 3x^6 - 2x^6 = x^6.

Therefore, the simplified expression 3x^7/x - 2x^2 * x^4 is equal to x^6.

2) To simplify the expression ab * (-2) * (4a)^3, we can apply the rules of exponents and perform the necessary calculations step by step.

First, let's simplify the exponent (4a)^3. When raising a term with an exponent to another exponent, we multiply the exponents. In this case, we have (4a)^3 = 4^3 * a^3 = 64a^3.

Next, let's simplify the multiplication ab * (-2) * 64a^3. When multiplying terms, we multiply their coefficients and add their exponents. In this case, we have -2 * 64 * a * a^3 = -128a^4.

Therefore, the simplified expression ab * (-2) * (4a)^3 is equal to -128a^4.

Please let me know if you have any further questions!