Question

Решите уравнение: (x-5)(x+5)=(x-3)^2+2

Answer 1

$(x-5)(x+5)=(x-3) ^{2} +2 \\ x^2-5 ^2= (x-3)^2+2 \\ x^2-25= x^2-6x+9+2 \\ 6x-9=27 \\ 6x= 27+9 \\ 6x= 36 \\ x=6$