Question

log₃(6+x)=2 Найдите корень уравнения. Распишите все подробно

Answer 1

$log_{a}b=c$

$a^{c}=b$

6+x=3^2

6+x=9

x=9-6

x=3

Ответ: 3.

Answer 2

To find the root of the equation log₃(6+x) = 2, we can start by rewriting the equation in exponential form. In exponential form, the equation becomes:

3^2 = 6 + x

Simplifying the equation, we have:

9 = 6 + x

To isolate the variable x, we can subtract 6 from both sides of the equation:

9 - 6 = x

Simplifying further, we get:

3 = x

Therefore, the root of the equation log₃(6+x) = 2 is x = 3.

Please let me know if you have any further questions!