Question

B1.Найдите sin a, если cos a=5/12 и p

Answer 1

Sinα = √(1 - Cos²α) = √(1 - 25/144)= √(119/144)= √119/12

Answer 2

I found some web search results that might help you with your question. Here is a summary of what I learned:

- To find the value of sin a, you need to use the Pythagorean identity: sin² a + cos² a = 1 . This means that if you know the value of cos a, you can find the value of sin a by solving for it in the equation. - In your case, cos a = 5/12, so you can plug this value into the equation and get: sin² a + (5/12)² = 1. Simplifying, you get: sin² a = 1 - 25/144 = 119/144. Taking the square root of both sides, you get: sin a = ±√(119/144) = ±√119/12. - However, this is not the final answer, because you also need to consider the quadrant where the angle a is located. Since you are given that p < a, this means that a is greater than pi radians or 180 degrees. This implies that a is either in the third or fourth quadrant, where cos a is negative . - Since cos a = 5/12 is positive, this contradicts the condition that p < a. Therefore, there is no solution for sin a in this case. You might want to check if you typed the question correctly, or if there is a typo in the original source.