Question

Log1/2(5x+3)>=-1/2 Решите пожалуйста, очень нужно, заранее спасибо

Answer 1

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Answer 2

Solving the Inequality Log1/2(5x+3) >= -1/2

To solve the inequality Log1/2(5x+3) >= -1/2, we need to isolate the variable x.

1. Start by rewriting the inequality in exponential form: 1/2^(-1/2) <= 5x + 3.

2. Simplify the left side of the inequality: √2 <= 5x + 3.

3. Subtract 3 from both sides of the inequality: √2 - 3 <= 5x.

4. Divide both sides of the inequality by 5: (√2 - 3)/5 <= x.

Therefore, the solution to the inequality Log1/2(5x+3) >= -1/2 is x >= (√2 - 3)/5.

Please note that this solution is based on the given inequality and may not be applicable in all contexts.