Question

Решите уравнение 2x+3x+4=14, 7z-z+5=11, 8y-4y-12=-50,-10+x+x=-26,10y-3y-9=40,-y+8-14y=23

Answer 1

1)5x+4=14

5x=14-4

5x=10

x=10:5

x=2

2)6z+5=11

6z=11-5

6z=6

z=1

3) 4y-12=-50

4y=-50+12

4y=-38

y=-9,5

4)-10+2x=-26

2x=-26+10

2x=-16

x=-8

5)7y-9=40

7y=40+9

7y=49

y=7

-15y+8=23

-15y=23-8

-15y=15

y=-1

хороших оценок)

Answer 2

1) 2x + 3x + 4 = 14 5x + 4 = 14 5x = 10 x = 2

2) 7z - z + 5 = 11 6z + 5 = 11 6z = 6 z = 1

3) 8y - 4y - 12 = -50 4y - 12 = -50 4y = -38 y = -9.5

4) -10 + x + x = -26 2x - 10 = -26 2x = -16 x = -8

5) 10y - 3y - 9 = 40 7y - 9 = 40 7y = 49 y = 7

6) -y + 8 - 14y = 23 -15y + 8 = 23 -15y = 15 y = -1

Таким образом, решения уравнений: 1) x = 2 2) z = 1 3) y = -9.5 4) x = -8 5) y = 7 6) y = -1