Question

От пристаней A и B по реке скорость которой 2 км/ч одновременно вышли навстречу друг другу два одинаковых катера и всретелись через 7 чачов. Найти собственную скорость катеров если известно что расстояние от А до В равно 347 км и катер идущий по течению сделала в пути полуторачосовую остановку.

Answer 1

(v+2)(7-1.5)+(v-2)7=347

5.5v+11+7v-14=347

12.5v-3=347

12.5v=350

v=28

Ответ: 28 км/ч

Answer 2

Надеюсь на "лучшее решение" :)
Решение на картинке 

Answer 3

Problem Analysis

We are given that two identical boats, traveling at a speed of 2 km/h each, start simultaneously from points A and B on a river and meet after 7 hours. We need to find the speed of the boats if the distance between points A and B is 347 km, and one of the boats makes a 1.5-hour stop during the journey.

Solution

Let's assume the speed of each boat is x km/h. Since the boats are traveling towards each other, their relative speed will be the sum of their individual speeds. Therefore, the relative speed of the boats is 2x km/h.

We can use the formula distance = speed × time to calculate the distance traveled by each boat. The boat traveling from point A will travel for 7 hours, and the boat traveling from point B will travel for 7 hours minus the 1.5-hour stop. The total distance traveled by both boats should be equal to the distance between points A and B, which is 347 km.

Let's set up the equation:

Distance traveled by boat from A + Distance traveled by boat from B = Distance between A and B

Using the formula distance = speed × time, we can rewrite the equation as:

7x + (7 - 1.5)x = 347

Simplifying the equation:

7x + 5.5x = 347

12.5x = 347

Solving for x:

x = 347 / 12.5

x ≈ 27.76

Therefore, the speed of each boat is approximately 27.76 km/h.

Answer

The speed of each boat is approximately 27.76 km/h.