Question

(1+x^2)(1-x^2+x^4)= (3-m)(9+3m+m^2)= (4+n^2)(16-4n^2+n^4)= (64-8z^3+z^6)(8+z^3)=

Answer 1

=1+x^6
=27-m^3
=48+n^6
=516+z^9

Answer 2

Я могу помочь вам решить эти уравнения. Вот подробные ответы:

(1+x^2)(1-x^2+x^4) = 1 - x^2 + x^4 + x^2 - x^4 + x^6 + x^4 - x^6 + x^8 = 1 + x^8

(3-m)(9+3m+m^2) = 27 + 9m + 3m^2 - 9m - 3m^2 - m^3 = 27 - m^3

(4+n^2)(16-4n^2+n^4) = 64 - 16n^2 + 4n^4 + 16n^2 - 4n^4 - n^6 + 4n^4 - n^6 + n^8 = 64 - 2n^6 + n^8

(64-8z^3+z^6)(8+z^3) = 512 + 64z^3 + 8z^6 - 64z^3 - 8z^6 - z^9 + 8z^6 + z^9 - z^12 = 512 + 8z^6 - z^12