Question

Чему равна сумма первых пяти членов арифметической прогрессии (а„), если а, = -10, а разность равна 10. пожалуйста

Answer 1

Формула суммы=((a1+d(n-1))2)*n

((-10+10(5-1))/2)*5=75

Ответ: 75 сумма первых пяти членов

Answer 2

50. скорее всего. пожалуйста

Answer 3

Calculating the Sum of the First Five Terms of an Arithmetic Progression

To calculate the sum of the first five terms of an arithmetic progression with the first term (a₁) equal to -10 and a common difference (d) equal to 10, we can use the formula for the sum of the first n terms of an arithmetic progression:

Sₙ = n/2 * (2a + (n-1)d)

Where: - Sₙ is the sum of the first n terms - n is the number of terms - a is the first term - d is the common difference

Calculation

Using the given values: - a = -10 - d = 10 - n = 5

We can calculate the sum of the first five terms of the arithmetic progression:

S₅ = 5/2 * (2*(-10) + (5-1)*10)

S₅ = 5/2 * (-20 + 4*10)

S₅ = 5/2 * (-20 + 40)

S₅ = 5/2 * 20

S₅ = 5 * 10

S₅ = 50

Therefore, the sum of the first five terms of the arithmetic progression is 50.

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