Question

Самолёт летел 4 часа со скоростью 600 км/ч. После этого приземлился на пол часа . Затем продолжил лететь со скоростью 750км/ч. Он прилетел на место на пол часа раньше чем бы летел с первой скоростью.найди время полёта и расстояние которое пролетел самолёт.

Answer 1

4×600=750×(х-0.5)
2400=750х-375
750х=2400+375
х=2775/750
х=3.7
3.7×750=2775
2775+2400=5175км
общее время полета без стоянки 3.7+4=7.7
самолет пролетел 5175км

Answer 2

Calculating the Flight Time and Distance Traveled

To calculate the flight time and distance traveled by the plane, we can use the information provided in the question and apply the formula: distance = speed × time.

Given: - Speed of the plane for the first 4 hours: 600 km/h - Speed of the plane after landing for 0.5 hours: 0 km/h (plane is on the ground) - Speed of the plane for the remaining flight time: 750 km/h - The plane arrived half an hour earlier than it would have if it had flown at the initial speed for the entire duration.

Let's denote the total flight time as T hours, the distance traveled during the first 4 hours as D1, and the remaining distance as D2.

We can set up the following equations based on the given information: 1. D1 = 600 km/h × 4 h 2. D2 = 750 km/h × (T - 4.5) (T - 4.5 represents the remaining flight time after the 0.5-hour landing) 3. D1 + D2 = 750 km/h × (T - 0.5) (total distance traveled)

To solve for T and the total distance traveled, we can use these equations.

Solving for Flight Time and Distance Traveled

Using the equations above, we can solve for the flight time and the total distance traveled by the plane.

1. Calculating D1 (Distance traveled in the first 4 hours): - D1 = 600 km/h × 4 h - D1 = 2400 km

2. Calculating D2 (Distance traveled after the 0.5-hour landing): - D2 = 750 km/h × (T - 4.5)

3. Calculating the total distance traveled: - D1 + D2 = 750 km/h × (T - 0.5)

4. Using the fact that the plane arrived half an hour earlier than it would have if it had flown at the initial speed for the entire duration: - D1 + D2 = 750 km/h × (T - 0.5) - D1 + D2 = 600 km/h × T (since the plane arrived half an hour earlier)

5. Solving for T (Total flight time): - 2400 km + 750 km/h × (T - 4.5) = 600 km/h × T - 2400 km + 750 km/h × T - 750 km/h × 4.5 = 600 km/h × T - 2400 km + 750 km/h × T - 3375 km = 600 km/h × T - 750 km/h × T - 600 km/h × T = 3375 km - 2400 km - 150 km/h × T = 975 km - T = 975 km / 150 km/h - T = 6.5 hours

6. Calculating the total distance traveled: - D1 + D2 = 600 km/h × T - 2400 km + 750 km/h × (6.5 - 4.5) = 600 km/h × 6.5 - 2400 km + 750 km/h × 2 = 3900 km - 2400 km + 1500 km = 3900 km - 3900 km = 3900 km

Conclusion

The total flight time of the plane was 6.5 hours, and the total distance traveled by the plane was 3900 km.