Question

Проходит ли график функции у = - 5х + 11 через точку: а) М (6; -41) б) N (-5; 36)?

Answer 1

у=-5х+11

а) М(6; 41), подставляем в формулу: -5*6+11= -30+11=-19 не = 41 не проходит

б) N(-5; 36), подставляем в формулу: -5*(-5)+11= 25+11=36  =  36 проходит

Answer 2

В уравнение подставляем координаты точек:

-41=-5*6+11

правая часть равенства равна -19, то есть первая точка не принадлежит графику

Проверим вторую точку:

36=-5*(-5)+11

Равенство верно, значит, точка принадлежит графику

Answer 3

Checking the Function's Graph through Given Points

To determine if the function's graph passes through the given points, we can substitute the x-values of the points into the function and check if the resulting y-values match the given y-values.

Point (6, -41)

Substituting x = 6 into the function u = -5x + 11: - u = -5(6) + 11 - u = -30 + 11 - u = -19

The function's graph does not pass through point M(6, -41) as the calculated y-value (-19) does not match the given y-value (-41).

Point (-5, 36)

Substituting x = -5 into the function u = -5x + 11: - u = -5(-5) + 11 - u = 25 + 11 - u = 36

The function's graph passes through point N(-5, 36) as the calculated y-value (36) matches the given y-value (36).

Conclusion: The function's graph passes through point N(-5, 36) but does not pass through point M(6, -41).