Question

Кто поможет с системкой x^2-y^2=3 x-y=4

Answer 1

(x-y)(x+y)=3
x-y=4
(x+y)*4=3
(x+y)=3/4
x=y+4
y+4+y=0,75
2y=0,75-4
2y=-3,25
y=-1,625
x=2,375

Answer 2

X=y+4. подставляем в 1 уравнение: (y+4)^2-y^2=3; y^2+8y+16-y^2-3=0; 8y+13=0; 8y= -13; y= -13/8= -1 5/8. x= -1 5/8+4=2 3/8. Ответ:( 2 3/8: -1 5/8). 

Answer 3

Solving the System of Equations x^2 - y^2 = 3 and x - y = 4

To solve the system of equations x^2 - y^2 = 3 and x - y = 4, we can use the substitution method or the elimination method. Let's use the substitution method to solve this system of equations.

First, let's solve the equation x - y = 4 for x: x = y + 4.

Now, we can substitute x = y + 4 into the equation x^2 - y^2 = 3: (y + 4)^2 - y^2 = 3.

Expanding and simplifying the equation: y^2 + 8y + 16 - y^2 = 3, 8y + 16 = 3, 8y = -13, y = -13/8.

Now that we have found the value of y, we can substitute it back into x = y + 4 to find the value of x: x = (-13/8) + 4, x = 23/8.

So, the solution to the system of equations x^2 - y^2 = 3 and x - y = 4 is: x = 23/8 and y = -13/8.