Question

1.2х^2-12х-1=2(1-2х)решите пожалуйста

Answer 1

1.2х^2-12х-1=2(1-2х)
1,2x²-12x-1-2+4x=0
1,2x²-8x-3=0
12x²-80x-30=0
6x²-40x-15=0
D=1600+360=1960
√D=14√10
x1=(40-14√10)/12=(20-7√10)/3
x2=(20+7√10)/3

Answer 2

Solving the Equation 1.2x^2 - 12x - 1 = 2(1 - 2x)

To solve the equation 1.2x^2 - 12x - 1 = 2(1 - 2x), we can follow these steps:

1. Expand and simplify the equation. 2. Rearrange the terms to isolate the variable x. 3. Use the quadratic formula to solve for x.

Let's go through each step in detail.

Step 1: Expand and Simplify the Equation

First, let's expand and simplify the equation 1.2x^2 - 12x - 1 = 2(1 - 2x):

1.2x^2 - 12x - 1 = 2 - 4x

Now, we have the equation in a simplified form.

Step 2: Rearrange the Terms to Isolate the Variable x

Next, we'll rearrange the terms to isolate the variable x on one side of the equation. We'll move all the terms to one side and set the equation equal to zero:

1.2x^2 - 12x - 1 - 2 + 4x = 0 1.2x^2 - 8x - 3 = 0

Now, the equation is in the form ax^2 + bx + c = 0, where a = 1.2, b = -8, and c = -3.

Step 3: Use the Quadratic Formula to Solve for x

We can use the quadratic formula to solve for x:

Quadratic Formula: For an equation in the form ax^2 + bx + c = 0, the solutions for x are given by: \[ x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}} \]

Using the values of a, b, and c from our equation, we can calculate the solutions for x.

Calculating the Solutions for x

Using the quadratic formula, we can calculate the solutions for x:

\[ x = \frac{{-(-8) \pm \sqrt{{(-8)^2 - 4(1.2)(-3)}}}}{{2(1.2)}} \]

\[ x = \frac{{8 \pm \sqrt{{64 + 14.4}}}}{{2.4}} \]

\[ x = \frac{{8 \pm \sqrt{{78.4}}}}{{2.4}} \]

So, the solutions for x are:

\[ x = \frac{{8 + \sqrt{{78.4}}}}{{2.4}} \] \[ x = \frac{{8 - \sqrt{{78.4}}}}{{2.4}} \]

These are the solutions for the given equation 1.2x^2 - 12x - 1 = 2(1 - 2x).