Question

помогите пжл.на тему многочлен.разложите на множители.1.ас+bс+2а+2b.2.а кубе-2а квадрате +а-2.3.3х+9-ху-3упомогите ПОЖАЛУЙСТА.оч оч оч срочно надо

Answer 1

a(c+2)+b(c+2)=(a+b)(c+2)    1

3(x+3)-y(x+3)=(3-y)(x+3)          3

Answer 2

Factoring Polynomials

Factoring polynomials involves expressing a polynomial as a product of its factors. Let's factor the given polynomials:

1. Polynomial: as + bc + 2a + 2b

To factor this polynomial, we can group the terms:

as + bc + 2a + 2b = (as + 2a) + (bc + 2b)

Now, we can factor out the common terms from each group:

(as + 2a) + (bc + 2b) = a(s + 2) + b(c + 2)

Therefore, the factored form of the polynomial as + bc + 2a + 2b is a(s + 2) + b(c + 2).

2. Polynomial: a^3 - 2a^2 + a - 2

To factor this polynomial, we can look for common factors. In this case, we can factor out the common factor of (a - 2):

a^3 - 2a^2 + a - 2 = (a - 2)(a^2 + 1)

Therefore, the factored form of the polynomial a^3 - 2a^2 + a - 2 is (a - 2)(a^2 + 1).

3. Polynomial: 3x + 9 - xu - 3u

To factor this polynomial, we can group the terms:

(3x + 9) - (xu + 3u) = 3(x + 3) - u(x + 3)

Now, we can factor out the common factor of (x + 3):

3(x + 3) - u(x + 3) = (x + 3)(3 - u)

Therefore, the factored form of the polynomial 3x + 9 - xu - 3u is (x + 3)(3 - u).

I hope this helps! Let me know if you have any further questions.