Question

Сравните: √34+√38 и 12

Answer 1

Корень из 34=5,8,а корень из 38=6,1
5,8+6,1=11,9<12 

Answer 2

I can help you with your math question. To compare $$\sqrt{34}+\sqrt{38}$$ and $$12$$, we can use the following steps:

- Square both sides of the inequality $$\sqrt{34}+\sqrt{38} < 12$$ - Simplify the left side using the formula $$(a+b)^2 = a^2 + 2ab + b^2$$ - Subtract $$144$$ from both sides - Divide both sides by $$2$$ - Square both sides again - Simplify the left side using the formula $$\sqrt{ab} = \sqrt{a}\sqrt{b}$$ - Compare the left and right sides

The result is $$\sqrt{34}+\sqrt{38} < 12$$, which means that the sum of the square roots is less than $$12$$. You can also use an online calculator to check your answer. For more explanations and examples, you can visit these websites. I hope this helps.