Question

X^2-4x+4=0 найдите корни квадратного уравнения

Answer 1

$x^2-4x+4=0\\(x-2)^2=0\\x-2=0\\x=2\\\\\bf OTBET:\quad x=2$

Answer 2

x^2-4x+4=0

D=b^2-4ac=16-4*1*4=16-16=0

x=-b/2a=-4/2=-2

Ответ: x=-2

Answer 3

I can help you with your math question. To find the roots of a quadratic equation, you need to use the formula $$x_{1,2} = \frac{-b \pm \sqrt{D}}{2a}$$ where $$D = b^2 - 4ac$$ is the discriminant. In your case, the equation is $$x^2 - 4x + 4 = 0$$ so $$a = 1, b = -4, c = 4$$. Plugging these values into the formula, we get $$x_{1,2} = \frac{4 \pm \sqrt{(-4)^2 - 4 \cdot 1 \cdot 4}}{2 \cdot 1}$$ Simplifying, we get $$x_{1,2} = \frac{4 \pm \sqrt{0}}{2}$$ Since the square root of zero is zero, we get $$x_{1,2} = \frac{4}{2}$$ Therefore, the equation has only one root, which is $$x = 2$$

You can check your answer by plugging it back into the equation: $$2^2 - 4 \cdot 2 + 4 = 0$$ This is true, so the answer is correct.

If you want to learn more about quadratic equations and how to solve them, you can visit some of these websites: [Online calculator. Solving quadratic equations](https://ru.onlinemschool.com/math/assistance/equation/quadratic/), [Root Calculator - Symbolab](https://ru.symbolab.com/solver/roots-calculator), [Reference: Quadratic equations and their solutions](https://ru.onlinemschool.com/math/assistance/equation/quadratic/).