Question

Найдите производную функции:a) y=(x^2-3x+1)^7б) y=корень(x^2-3x+1)в) y=tg(3x-pi/4)г) y=cos^2 xПомогите хотя быс теми, какие знаете как решаются.Спасибо.

Answer 1

Производная в точке х0=2*8х0-3=16х0-3=16*1-3=13

Answer 2

Finding Derivatives of the Given Functions

a) For the function y = (x^2 - 3x + 1)^7: To find the derivative of the given function, we can use the chain rule, which states that if we have a function raised to a power, we can find its derivative by first finding the derivative of the outer function and then multiplying it by the derivative of the inner function.

The derivative of the given function is: y' = 7(x^2 - 3x + 1)^6 * (2x - 3) b) For the function y = sqrt(x^2 - 3x + 1): To find the derivative of the square root function, we can use the chain rule as well.

The derivative of the given function is: y' = (1/2) * (x^2 - 3x + 1)^(-1/2) * (2x - 3) c) For the function y = tan(3x - π/4): The derivative of the tangent function is the secant squared function. Therefore, the derivative of the given function is: y' = sec^2(3x - π/4) d) For the function y = cos^2(x): The derivative of the cosine squared function is: y' = -2cos(x)sin(x) These are the derivatives of the given functions. If you have any further questions or need additional assistance, feel free to ask!