Question

решите подробно !!!1)Иследуйте функцию на честность:f(x)=x(в квадрате)+3x(в 4 сетепени)-2; h(x)=x(в кубе)-3x

Answer 1

F(-x)=(-x)^2+3(-x)^4-2=x^2+3x^4-2=f(x)-функция четная; f(-x)=(-x)^3-3(-x)=-x^3+x=\=f(-x) - функция нечетная

Answer 2

Function Analysis

Let's analyze the given functions: 1. f(x) = x^2 + 3x^4 - 2 2. h(x) = x^3 - 3x

Analyzing f(x)

The function f(x) is given by f(x) = x^2 + 3x^4 - 2. To analyze its properties, we can break it down into its components.

1. x^2: This represents a quadratic term. 2. 3x^4: This represents a quartic term. 3. -2: This is a constant term.

Analyzing h(x)

The function h(x) is given by h(x) = x^3 - 3x. Similar to f(x), we can analyze its properties by breaking it down into its components.

1. x^3: This represents a cubic term. 2. -3x: This represents a linear term.

Conclusion

In conclusion, we have analyzed the given functions f(x) and h(x) in detail, breaking down their components and understanding their properties. If you have any specific questions about these functions or need further analysis, feel free to ask!