
В первом мешке в 3 раза больше картофеля, чем во втором. После того как из первого мешка взяли 30кг
картофеля, а во второй насыпали ещё 10 кг, в обоих мешках картофеля стало поровну. Сколько килограммов картофеля было в двух мешках первоначально

Ответы на вопрос




Problem Analysis
We are given two bags of potatoes, with the first bag containing three times as many potatoes as the second bag. After taking 30 kg of potatoes from the first bag and adding 10 kg to the second bag, the amount of potatoes in both bags became equal. We need to determine the initial weight of potatoes in both bags.
Solution
Let's assume the initial weight of potatoes in the second bag is x kg. According to the problem, the first bag contains three times as many potatoes as the second bag, so the initial weight of potatoes in the first bag is 3x kg.
After taking 30 kg of potatoes from the first bag, the weight of potatoes in the first bag becomes 3x - 30 kg. After adding 10 kg to the second bag, the weight of potatoes in the second bag becomes x + 10 kg.
Since the weight of potatoes in both bags became equal, we can set up the following equation:
3x - 30 = x + 10
Simplifying the equation, we get:
2x = 40
Dividing both sides of the equation by 2, we find:
x = 20
Therefore, the initial weight of potatoes in the second bag was 20 kg. Since the first bag contains three times as many potatoes, the initial weight of potatoes in the first bag was 3 * 20 = 60 kg.
So, initially, there were 60 kg of potatoes in the first bag and 20 kg of potatoes in the second bag.
Answer: The initial weight of potatoes in the first bag was 60 kg, and the initial weight of potatoes in the second bag was 20 kg.



Problem Analysis
We are given two bags of potatoes, and the amount of potatoes in the first bag is three times the amount in the second bag. After taking 30 kg of potatoes from the first bag and adding 10 kg to the second bag, the amount of potatoes in both bags became equal. We need to find the initial amount of potatoes in both bags.
Solution
Let's assume the initial amount of potatoes in the second bag is x kg. According to the problem, the amount of potatoes in the first bag is three times the amount in the second bag, so the initial amount of potatoes in the first bag is 3x kg.
After taking 30 kg of potatoes from the first bag, the remaining amount of potatoes in the first bag is 3x - 30 kg. After adding 10 kg to the second bag, the amount of potatoes in the second bag becomes x + 10 kg.
According to the problem, the amount of potatoes in both bags became equal. Therefore, we can set up the following equation:
3x - 30 = x + 10
Now, let's solve this equation to find the value of x.
3x - x = 10 + 30
2x = 40
x = 20
So, the initial amount of potatoes in the second bag is 20 kg. Since the amount of potatoes in the first bag is three times the amount in the second bag, the initial amount of potatoes in the first bag is 3 * 20 = 60 kg.
Therefore, the initial amount of potatoes in both bags was 60 kg in the first bag and 20 kg in the second bag.
Answer
The initial amount of potatoes in the first bag was 60 kg, and the initial amount of potatoes in the second bag was 20 kg.


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