Question

X^2-2x+5=3x+1 помогите решить пожалуйста

Answer 1

X²-2x+5=3x+1
x²-2x-3x+5-1=0
x²-5x+4=0
D=b²-4ac=25-4·1·4=9
x1=-b-√D÷2a=5-3÷2=1
x2=-b+√D÷2a=5+3÷2=4

Answer 2

X^2-5x+4=0(перенесли в одну сторону, нашли подобные слагаемые) X1=4 x2=1 (по теорема Виета)

Answer 3

Solving the Equation x^2 - 2x + 5 = 3x + 1

To solve the equation x^2 - 2x + 5 = 3x + 1, we can follow these steps:

Step 1: Move all the terms to one side of the equation to get a quadratic equation in standard form. In this case, we subtract 3x and 1 from both sides:

x^2 - 2x - 3x + 5 - 1 = 0

Simplifying, we have:

x^2 - 5x + 4 = 0

Step 2: Factor the quadratic equation. In this case, we can factor the equation as:

x^2 - 5x + 4 = (x - 4)(x - 1) = 0

Step 3: Set each factor equal to zero and solve for x. In this case, we have two equations:

x - 4 = 0 and x - 1 = 0

Solving these equations, we find:

x = 4 and x = 1

Therefore, the solutions to the equation x^2 - 2x + 5 = 3x + 1 are x = 4 and x = 1.