Question

Помогите решить срочно надо пожалуйста! !!!!!!

Answer 1

1) a) f'(x) = 2(x² -2x -3) * (2x -2)
    б) f'(x) = -2Sinx*tgx + 2Cosx*1/Cos²x = -2Sin²x/Cosx + 2/Cosx=
=(-2Sin²x +2)/Cosx = 2(-Sin²x +1)/Cosx = 2Cos²x/Cosx = 2Cosx
2)4/8 *Cosx/8 + 1/8Sinx/8 = 0
   4Cosx/8 + Sinx/8 = 0 | : Cosx/8
   4 + tgx/8 = 0
    tgx/8 = -4
x/8 = arctg(-4) + πk , k ∈Z
x = -8arctg4 + 8πk , k ∈Z
3) f'(x) = - 8/(2x +7)^5 + 3(1 - x)²
f'(-3) = -8 + 48 = 40
4) f(g(x)) = (√x)² - 4√x