Question

Умоляю! ПОМОГИТЕ! ПРОШУ,СРОЧНО НАДО

Answer 1

$\frac{(3-\sqrt8)\sqrt{3+\sqrt8}}{\sqrt2-1}=\frac{\sqrt{(3-\sqrt8)^2(3+\sqrt8)}}{\sqrt2-1}=\frac{\sqrt{(3-\sqrt8)(3^2-(\sqrt8)^2)}}{\sqrt2-1}=\\\\=\frac{\sqrt{(3-2\sqrt2)(9-8)}}{\sqrt2-1}=\frac{\sqrt{2-2\sqrt2+1}}{\sqrt2-1}=\frac{\sqrt{(\sqrt2-1)^2}}{\sqrt2-1}=\frac{\sqrt2-1}{\sqrt2-1}=1$