Question

Решить неравенство #4

Answer 1

$(x-1)^2*(x^2+3x+2)\ \textless \ =0 \\ x^2+3x+2=0 \\ D = 9-4*1*2 = 1\\ x_1,x_2= \frac{-3+-1}{2} \\ x_1 = -1 ; x_2 = -2 \\ (x-1)^2*(x+1)*(x+2)\ \textless \ =0 \\ -2 -1 1\\ --------------------------- \\ + - + + \\ Intger_{solution} \\ x [-2;-1]$