Question

Помогите пожалууйстаааааа!!

Answer 1

1).
а) =3x/2y.
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б) 5y/(y²-2y) =5y/y(y-2) =5/(y-2) .
в) (3a-3b)/(a²-b²) =3(a-b)/(a-b)(a+b) =3/(a+b).
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2).
а) (3-2a)/2a -(1-a²)/a² =(a(3-2a) -2(1-a²))/2a² =(3a-2a² - 2 +2a²)/2a² = (3a-2)/2a².
* * *3-2a)/2a -(1-a²)/a²=(3/2a -1 -1/a² +1) =3/2a -1/a² = (3a -2)/2a².
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б) (1/(3x+y) - 1/(3x -y) =(3x-y -3x-y)/(3x-y)(3x+y) =-2y/3x-y)(3x+y) 
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в) (4-3b)/(b² -2b) +3/(b-2) =(4-3b)/b(b -2) +3/(b-2) =(4-3b+3b)/b(b-2) =4/b(b-2).
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3) (x-6y²)/2y +3y = x/2y -3y +3y =x/2y || x=-8 ;y =0,1 || = -8/2*0,1 = -80/2 =-  40.
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 4) 2/(x-4) -(x+8)/(x² -16) -1/x =2/(x-4) -(x+8) / (x -4)(x +4)  -1/x =
(2x(x+4) -x(x+8)- (x²+16))/x(x -4)(x +4) =
(2x²+8x -x²- 8x-x²+16)/x(x -4)(x +4) =16/x(x-4)(x+4)..

Answer 2

Держи вычисление)))))))))))