Question

= Х-2

Answer 1

$\sqrt{x+10}=x-2\; ,\; \; OOF:\; \; x \geq 2\\\\x+10=x^2-4x+4\\\\x^2-5x-4=0\\\\D=25+16=41\\\\x_1=\frac{5-\sqrt{41}}{2}\notin OOF\\\\x_2=\frac{5+\sqrt{41}}{2}\in OOF \; \; -\; \; otvet$