Question

Люди помогите плиз, максимальное количество баллов . Два одинаковых квадрата площадью 64 квадратных сантиметров каждый сложили так что получился прямоугольник чему равен периметр полученного прямоугольника

Answer 1

Sквадрата=а·а
a=√s
a=√64
a=8
По всей видемости квадратя положили просто рядом. Значит ширина = 8 см, а длинна= 8·2=16
Р прямоугольника=(а+b)·2
Р=(16+8)·2=48

Answer 2

Сложить два квадрата=прямоугольник с шириной=8 см, длина =16 см. Р=(16+8)*2=48 см

Answer 3

Calculation of the Perimeter of the Rectangle

To find the perimeter of the rectangle formed by two identical squares with an area of 64 square centimeters each, we need to determine the dimensions of the rectangle.

Let's assume that the side length of each square is s. Since the area of each square is 64 square centimeters, we can set up the following equation:

s^2 = 64

Taking the square root of both sides, we find:

s = √64 = 8

Therefore, the side length of each square is 8 centimeters.

When the two squares are arranged to form a rectangle, the length of the rectangle will be equal to the sum of the side lengths of the squares, which is 8 + 8 = 16 centimeters. The width of the rectangle will be equal to the side length of one of the squares, which is 8 centimeters.

Now, we can calculate the perimeter of the rectangle using the formula:

Perimeter = 2 * (Length + Width)

Substituting the values, we get:

Perimeter = 2 * (16 + 8) = 2 * 24 = 48 centimeters

Therefore, the perimeter of the rectangle formed by two identical squares with an area of 64 square centimeters each is 48 centimeters.

Please let me know if there is anything else I can help you with!