Question

tgX*(2 - cosX)=0 помогите решить пожалуйста)))

Answer 1

tgx (2 - cos x)=0

tg x=0 или 2-cosx=0

x=pi\k        ур-е 2-cosx=0 не имеет корней 

Answer 2

Equation: tgX*(2+-cosX) = 0

To solve the equation tgX*(2+-cosX) = 0, we need to find the values of X that satisfy the equation. Let's break down the equation and solve it step by step.

1. First, let's consider the term tgX. The tangent function (tgX) is equal to zero when X is an integer multiple of π (pi). So, we have the condition X = nπ, where n is an integer.

2. Next, let's consider the term (2+-cosX). The cosine function (cosX) can take values between -1 and 1. So, we have two cases to consider:

a. When cosX = 2: Since the cosine function can never be equal to 2, this case does not have any solutions.

b. When cosX = -2: Similarly, the cosine function cannot be equal to -2, so this case also does not have any solutions.

Therefore, the only solutions to the equation tgX*(2+-cosX) = 0 are the values of X that satisfy the condition X = nπ, where n is an integer.

Please let me know if you need any further assistance!