Question

Два Муравья отправились в гости к Стрекозе. Один всю дорогу прополз, а второй первую половину пути ехал на Гусенице, что было в два раза медленнее, чем ползти, а вторую половину скакал на Кузнечике, что было в 10 раз быстрее. Какой Муравей первым придет в гости, если они вышли одновременно?

Answer 1

Второй муравей начал свое ускорение когда первый уже прошел 2\3 дистанции. Если первый муравей не изменял скорость, то просто получается, что второй муравей прошел общую дистанцию в 8 раз быстрее первого. 10-2=8

Answer 2

Наверно второй так как он сначала был на гусинице а потом на кузнечке что было в 10раз быстрее чем тот полз в 2 раза быстрее когда тот ехал на гусинице
мой ответ

Answer 3

Problem Analysis

Two ants are traveling to visit a dragonfly. One ant crawls the entire way, while the other ant rides a caterpillar for the first half of the journey, which is twice as slow as crawling, and then jumps on a grasshopper for the second half of the journey, which is ten times faster than crawling. We need to determine which ant will arrive first if they both start at the same time.

Solution

Let's assume that the distance between the ants and the dragonfly is D.

The first ant crawls the entire distance, so its speed is 1 unit of distance per unit of time.

The second ant rides a caterpillar for the first half of the journey, which is twice as slow as crawling. Therefore, its speed is 1/2 unit of distance per unit of time.

For the second half of the journey, the ant jumps on a grasshopper, which is ten times faster than crawling. Therefore, its speed is 10 units of distance per unit of time.

To find out which ant arrives first, we need to compare the time it takes for each ant to travel the entire distance.

Let's calculate the time it takes for each ant to travel the entire distance:

- The first ant takes D units of time to crawl the entire distance. - The second ant takes D/2 units of time to ride the caterpillar for the first half of the journey, and D/10 units of time to jump on the grasshopper for the second half of the journey. Therefore, the total time for the second ant is D/2 + D/10 = (5D + D)/10 = 6D/10 = 3D/5 units of time.

Comparing the times, we can see that the first ant takes less time to travel the entire distance than the second ant. Therefore, the first ant will arrive first.

Answer

The first ant will arrive first if they both start at the same time.