Question

ПОЖАЛУЙСТА надо решить!

Answer 1

$\dfrac{x^2 - 9}{2x^2 - 4x - 6} = \dfrac{(x - 3)(x + 3)}{2(x^2 - 2x - 3)} = \dfrac{(x -3 )(x + 3)}{2(x^2 - 2x + 1 - 4)} = \\ \\ = \dfrac{(x - 3)(x + 3)}{2((x - 1)^2 - 2^2)} = \dfrac{(x - 3)(x + 3)}{2(x - 1 - 2)(x - 1 + 2)} = \\ \\ = \dfrac{(x - 3)(x + 3)}{2(x - 3)(x + 1)} = \dfrac{x + 3}{2x + 2 }$