Question

Решите систему уравнений методом алгебраического сложения х в квадрате +у в квадрате=14 и х в квадрате +2у=18"

Answer 1

Мне кажется, не уверена. что правильно
 ответ:
( +-Корень из 10; 4 )

домножаем второе выражение на (-1), затем складываем, получается вроде бы
-1y=-4 /:(-1)
y=4 , тогда x^2+8=18
                  x^2=10
                  x= +-корень из  10 и 4
Ответ: (-Корень из 10;4) (Корень из 10;4)

Answer 2

Solution to the System of Equations using the Method of Algebraic Addition

To solve the system of equations:

Equation 1: x^2 + y^2 = 14

Equation 2: x^2 + 2y = 18

We can use the method of algebraic addition to eliminate one variable and solve for the other.

To eliminate the x^2 term, we can subtract Equation 2 from Equation 1:

(x^2 + y^2) - (x^2 + 2y) = 14 - 18

Simplifying the equation gives:

y^2 - 2y = -4

Now, let's solve this quadratic equation for y.

To factor the equation, we can rewrite it as:

y^2 - 2y + 1 = -4 + 1

(y - 1)^2 = -3

Taking the square root of both sides, we get:

y - 1 = ±√(-3)

Since the square root of a negative number is not a real number, this equation has no real solutions. Therefore, the system of equations has no real solutions.

Please let me know if you need any further assistance!