Question

Первое пож-ста,дам лучший!

Answer 1

A) SQRT(1/4)=1/2
CBRT(-2 11/8)=CBRT(-27/8)=-3/2
SQRT(625)=25
1/2-3/2+25=-1+25=24;

b) FIRT(2^6*3^4)*FIRT(2^4*3)=FIRT(2^6*3^4*2^4*3)=FIRT(2^10*3^5)=2^2*3=4*3=12.

Answer 2

$\sqrt{ \frac{1}{4} }+ \sqrt[3]{-2 \frac{11}{8} }+ \sqrt{625}= \frac{1}{2}+ \sqrt[3]{- \frac{27}{8}}+25= \frac{1}{2}- \frac{3}{2}+25= \\ 0,5-1,5+ 25=24 \\ \sqrt[5]{2^6*3^4} * \sqrt[5]{2^4*3}=2^ \frac{6}{5}*3^ \frac{4}{5}*2^ \frac{4}{5}*3^ \frac{1}{5}=2^ \frac{6}{5}^+^ \frac{4}{5}*3^ \frac{4}{5}^+^ \frac{1}{5}=2^2*3^1= \\ 4*3=12$