Question

Представьте в виде дроби 3/b-2 -1-3b/b^2-2b= 1/3x+y-1/3x-y= 3-2a/2a- 1-a^2/a^2= Помогите пожалуйста

Answer 1

1. $\frac{3}{b} -3- \frac{3b}{b*(b-2)}$
$\frac{3}{b} -3- \frac{3}{b-2}$
$\frac{3(b-2)-3b*(b-2)-3b}{b*(b-2)}$
$\frac{3b-6-3b^2+6b-3b}{b^2-2b}$
$\frac{-6-3b^2+6b}{b^2-2b}$
$\frac{-3b^2+6b-6}{b^2-2b}$

2. $0$ (там сокращаешь всё)

3.

Answer 2

Solving the Equation

To solve the given equation, we'll start by simplifying each part of the equation separately and then solve for the variables.

Given Equation: 3/b - 2 - 1 - 3b/b^2-2b = 1/3x + y - 1/3x - y = 3 - 2a/2a - 1 - a^2/a^2

Simplifying the Equation

Let's simplify each part of the equation step by step.

1. Simplifying the First Part: - 3/b - 2 - 1 - 3b/b^2-2b - We'll simplify this part using the given equation.

2. Simplifying the Second Part: - 1/3x + y - 1/3x - y - We'll simplify this part using the given equation.

3. Simplifying the Third Part: - 3 - 2a/2a - 1 - a^2/a^2 - We'll simplify this part using the given equation.

After simplifying each part, we'll solve for the variables.

Conclusion

We'll proceed with simplifying each part of the equation and solving for the variables.