Question

Выяснить, является ли данная функция чётной или нечётной (с решением)

Answer 1

Y=cos(x-π/2)-x²
cos(x-π/2)=cos(-(π/2-x))=cos(π/2-x)=sinx

y=sinx-x²
y(-x)=sin(-x)-(-x)²
y(-x)=-sinx-x²
y(-x)≠y(x)
y(-x)≠-y(x)
ответ: данная функция ни четная, ни нечетная.

Answer 2

Determining if a Function is Even or Odd

To determine whether a given function is even or odd, we need to analyze its symmetry properties.

Even Function: A function is considered even if it satisfies the condition f(x) = f(-x) for all x in its domain. In other words, an even function is symmetric with respect to the y-axis.

Odd Function: A function is considered odd if it satisfies the condition f(x) = -f(-x) for all x in its domain. In other words, an odd function is symmetric with respect to the origin.

Now, let's analyze the given function to determine if it is even or odd.

Unfortunately, the provided search snippets do not contain enough information about the specific function in question. To accurately determine whether the function is even or odd, we need the actual function or more details about its properties.

If you can provide the function or additional information, I would be happy to help you determine its symmetry properties.