Question

4х(2х-7)+3х(5-2х)=2х(в квадрате) +39. Помогите пожалуйста(

Answer 1

8х²-28х+15х-6х²=2х²
8х²-6х²-2х²-28х+15х=0
-13х=0
х=0

Answer 2

Solving the Equation

To solve the given equation 4x(2x-7) + 3x(5-2x) = 2x^2 + 39, we can follow these steps:

1. Expand and simplify the left-hand side of the equation. 2. Set the equation to zero and solve for x.

Step 1: Expand and Simplify

Expanding and simplifying the left-hand side of the equation: 4x(2x-7) + 3x(5-2x) = 2x^2 + 39

Expanding the terms: 8x^2 - 28x + 15x - 6x^2 = 2x^2 + 39

Combining like terms: 2x^2 - 13x = 2x^2 + 39

Step 2: Solve for x

Subtracting 2x^2 from both sides: -13x = 39

Dividing by -13: x = -3

So, the solution to the equation 4x(2x-7) + 3x(5-2x) = 2x^2 + 39 is x = -3.

I hope this helps! If you have any other questions or need further assistance, feel free to ask.