Question

10x+1=-8 уравнение а^2-4x=12 уравнение 4(x-7)=3x уравнение 3x^2-2x-2=0 уравнение

Answer 1

10x=-9|:10       x=-(9/10)
4(x-7)=3x        4x-28=3x   x=28
$4 \frac{1}{2}$x² -2x-2=0 
D=(-2)²-4×4,5×(-2)=-36 -корня отрицательного числа нет, значит не решаеться.

Answer 2

1) 10x + 1 = -8 To solve for x, first subtract 1 from both sides: 10x = -9 Then, divide both sides by 10: x = -9/10

2) a^2 - 4x = 12 We don't have enough information to solve for a or x, as we need one more equation or a given value for a or x.

3) 4(x-7) = 3x First, distribute the 4 on the left side: 4x - 28 = 3x Subtract 3x from both sides: x - 28 = 0 Add 28 to both sides: x = 28

4) 3x^2 - 2x - 2 = 0 To solve for x, we can use the quadratic formula: x = (-(-2) ± √((-2)^2 - 4*3*(-2)))/(2*3) x = (2 ± √(4 + 24))/6 x = (2 ± √28)/6 x = (2 ± 2√7)/6 x = (1 ± √7)/3

So the solutions for this equation are x = (1 + √7)/3 and x = (1 - √7)/3.