Question

Из пункта А в пункт В вышел товарный поезд. спустя 2ч вслед за ним вышел скорый поезд,который шел со скоростью ,на 30 км ч большей,чем товарный .через 10 ч после своего выхода скорый поезд,обогнав товарный,находился от него на расстоянии 220км.найти скорость товарного поезда. СРОЧНО ПРОШУ РЕШЕНИЕ ПОДРОБНО

Answer 1

Х км/ч - скорость товарного поезда, (х+30) км/ч - скорость скорого поезда.
10ч - время скорого поезда, 12 ч- время товарного
скорый поезд пройдет на 220 км больше
10(х+30)-12х=220
10х+300-12х=220
-2х=220-300
-2х=-80
х=-80:(-2)
х=40
40км/ч скорость товарного поезда

Answer 2

Problem Analysis

We are given that a freight train left point A and after 2 hours, a fast train left point A following the freight train. The fast train was traveling at a speed 30 km/h faster than the freight train. After 10 hours from its departure, the fast train overtook the freight train and was 220 km ahead of it. We need to find the speed of the freight train.

Solution

Let's assume the speed of the freight train is x km/h. Since the fast train is traveling 30 km/h faster, its speed will be (x + 30) km/h.

We can use the formula distance = speed × time to calculate the distances traveled by both trains.

The freight train traveled for a total of (2 + 10) = 12 hours. Therefore, the distance traveled by the freight train is 12x km.

The fast train traveled for a total of 10 hours. Therefore, the distance traveled by the fast train is 10(x + 30) km.

According to the problem, the fast train overtook the freight train and was 220 km ahead of it. This means that the distance traveled by the fast train is equal to the distance traveled by the freight train plus 220 km.

Setting up the equation: 10(x + 30) = 12x + 220

Now, let's solve this equation to find the value of x.

Calculation

10(x + 30) = 12x + 220 10x + 300 = 12x + 220 10x - 12x = 220 - 300 -2x = -80 x = -80 / -2 x = 40

Answer

The speed of the freight train is 40 km/h.

Verification

Let's verify our answer by substituting the value of x into the equation: 10(x + 30) = 12x + 220 10(40 + 30) = 12(40) + 220 10(70) = 480 + 220 700 = 700

The equation is balanced, which means our answer is correct.

Therefore, the speed of the freight train is 40 km/h.