Question

Дана линейная функция y=kx+4 при каком значении k график этой функции пересекает ось абцисс в точке с абциссой 3

Answer 1

Точка пересечения х=-3   у=0
0=-3к+4       3к=4       к=4/3

Answer 2

Finding the Value of k

To find the value of k at which the graph of the linear function y = kx + 4 intersects the x-axis at the point with an x-coordinate of 3, we can substitute the x-coordinate into the equation and solve for k.

Substituting x = 3 into the equation y = kx + 4, we get:

y = k(3) + 4

Simplifying further, we have:

y = 3k + 4

Since the point of intersection lies on the x-axis, the y-coordinate of the point is 0. Therefore, we can set y = 0 in the equation:

0 = 3k + 4

Now, we can solve for k:

3k + 4 = 0

Subtracting 4 from both sides:

3k = -4

Dividing both sides by 3:

k = -4/3

Therefore, the graph of the linear function y = kx + 4 intersects the x-axis at the point with an x-coordinate of 3 when k = -4/3.

Answer

The value of k at which the graph of the linear function y = kx + 4 intersects the x-axis at the point with an x-coordinate of 3 is k = -4/3.