Question

Два велосипедиста отправляются одновременно навстречу друг другу из двух пунктов,расстояние между которыми 60 км,и встречаются через 2 я. Определите скорость каждого велосипедиста, если у одного она на 2 км/ч больше, чем у другого.

Answer 1

Пусть х км/ч движется первый велосипедист, тогда у другого велосипедиста скорость будет (х+2) км/ч. 
Составим уравнение: х*2+2(х+2)=60
Решим уравнение: 2х+2х+4=60
4х=56
х=14
х+2=16

Answer 2

Problem Analysis

We have two cyclists who start simultaneously from two different points and meet each other after 2 hours. The distance between the two points is 60 km. One cyclist's speed is 2 km/h faster than the other. We need to determine the speed of each cyclist.

Solution

Let's assume the speed of the slower cyclist is v km/h. Therefore, the speed of the faster cyclist will be v + 2 km/h.

To find the speed of each cyclist, we can use the formula: speed = distance / time.

The slower cyclist covers a distance of 60 km in 2 hours, so their speed is 60 km / 2 hours = 30 km/h.

The faster cyclist's speed is 2 km/h faster than the slower cyclist's speed, so their speed is 30 km/h + 2 km/h = 32 km/h.

Therefore, the speed of the slower cyclist is 30 km/h and the speed of the faster cyclist is 32 km/h.

Answer

The speed of the slower cyclist is 30 km/h and the speed of the faster cyclist is 32 km/h.