Question

What is the positive difference between the square of the sum of the first five positive integers and the sum of the first five positive perfect squares

Answer 1

Ответ:

170

Объяснение:

(1+2+3+4+5)^2=$15^{2}$ = 225

$1^{2}$+$2^{2}$+$3^{2}$+$4^{2}$+$5^{2}$=55

225-55=170

Answer 2

The positive difference between the square of the sum of the first five positive integers and the sum of the first five positive perfect squares can be calculated as follows:

1. Square of the sum of the first five positive integers: - The first five positive integers are 1, 2, 3, 4, and 5. - The sum of these integers is 1 + 2 + 3 + 4 + 5 = 15. - The square of 15 is 15^2 = 225.

2. Sum of the first five positive perfect squares: - The first five positive perfect squares are 1^2, 2^2, 3^2, 4^2, and 5^2. - The sum of these perfect squares is 1^2 + 2^2 + 3^2 + 4^2 + 5^2 = 1 + 4 + 9 + 16 + 25 = 55.

3. Positive difference: - The positive difference between the square of the sum of the first five positive integers and the sum of the first five positive perfect squares is 225 - 55 = 170.

Therefore, the positive difference is 170.

[[1]](https://zenodo.org/record/46021/files/9781329899971_frontcover_content_backcover.pdf)