Question

Решить систему уравнения {2х+9у-2=0 {8х-15у+43=0 Смотреть ответ orichimaru0 orichimaru0 Объяснение: вот надеюсь что правильно

Answer 1

#### System of Equations Solution To solve the system of equations: Equation 1: 2x + 9y - 2 = 0 Equation 2: 8x - 15y + 43 = 0 We can use the method of substitution or elimination to find the values of x and y that satisfy both equations. Let's solve the system using the method of substitution: 1. Solve Equation 1 for x: 2x + 9y - 2 = 0 2x = -9y + 2 x = (-9y + 2) / 2 x = -4.5y + 1 2. Substitute the value of x in Equation 2: 8x - 15y + 43 = 0 8(-4.5y + 1) - 15y + 43 = 0 -36y + 8 - 15y + 43 = 0 -51y + 51 = 0 -51y = -51 y = -51 / -51 y = 1 3. Substitute the value of y back into Equation 1 to find x: x = -4.5y + 1 x = -4.5(1) + 1 x = -4.5 + 1 x = -3.5 Therefore, the solution to the system of equations is x = -3.5 and y = 1. Please note that the solution provided is based on the given equations and the method of substitution.